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<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Selected papers | Quantum Research Center</title><link>https://quantumresearch.center/news/papers/</link><atom:link href="https://quantumresearch.center/news/feed.xml" rel="self" type="application/rss+xml"/><description>Recent arXiv papers in quantum foundations, computing, and information, with explanations of their transferable methods.</description><language>en</language><lastBuildDate>Sun, 08 Nov 2026 00:00:00 +0000</lastBuildDate><item><title>Certifying the Rydberg-exposure limit of a globally driven controlled-Z gate</title><link>https://quantumresearch.center/news/papers/2611.07388/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.07388/</guid><pubDate>Sun, 08 Nov 2026 00:00:00 +0000</pubDate><category>Quantum computing</category><description>Neutral-atom CZ gates excite atoms to Rydberg states, and decay from those states is a leading source of gate error and atom loss, with loss probability about \Gamma T_R for average Rydberg time T_R. Can pulse shaping and longer gates make the exposure C=\Omega_{\max}T_R arbitrarily small when one global laser drives both atoms, with perfect blockade? Numerical optimal control had reached C\approx2.936, but no lower bound valid for all pulses existed. No: for every exact globally driven CZ gate in the perfect-blockade model, of any duration, 2.9312\le C_*&lt;2.9359. The lower bound comes from a sum-of-squares certificate verified exactly over \mathbb Q(\sqrt2); the upper bound from an interval-arithmetic (Krawczyk) proof that an exact CZ pulse exists near a numerical candidate. The unrounded bounds differ by less than 0.16%.</description></item><item><title>Efficient Pauli truncation from operator stabilizer Rényi entropy</title><link>https://quantumresearch.center/news/papers/2611.07545/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.07545/</guid><pubDate>Sun, 08 Nov 2026 00:00:00 +0000</pubDate><category>Quantum information</category><description>Classical simulation by Pauli propagation evolves an observable in the Heisenberg picture and keeps only its \chi largest Pauli coefficients. The operator stabilizer Rényi entropy (OSE) M^{(\alpha)}, the Rényi entropy of the squared Pauli coefficients, measures how spread out those coefficients are. For which Rényi indices does slow OSE growth guarantee that polynomially many terms give accurate expectation values for every input state, and when does fast growth rule it out? Linear growth of M^{(1)}, or power-law growth of M^{(\alpha)} for \alpha&gt;1, forces superpolynomially many terms for a fixed error over all states. Logarithmic growth for 0&lt;\alpha&lt;1/2 guarantees polynomially many terms suffice for every state, and the range is sharp: the operator I-2|0^N\rangle\langle0^N| has bounded OSE for every \alpha\ge1/2 but needs about 2^{N} terms. Averaged over low-average state ensembles the sufficient range extends to 0&lt;\alpha&lt;1. The paper also bounds cumulative error in iterative propagation and fixed-order OTOCs.</description></item><item><title>Non-unitary quantum butterfly effect: theory and experiment</title><link>https://quantumresearch.center/news/papers/2611.08152/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.08152/</guid><pubDate>Sun, 08 Nov 2026 00:00:00 +0000</pubDate><category>Foundations of quantum mechanics</category><description>Out-of-time-order correlators (OTOCs) measure how a local perturbation spreads through a many-body system, and in random unitary circuits they show a ballistic front behind which the signal saturates. Mid-circuit measurements are now routine, but how far and for how long an unread measurement disturbs the rest of a register is poorly characterised. What does the OTOC do when the evolution itself is non-unitary? The authors define an OTOC for quantum channels that bounds how much a perturbation at site y can change a measured expectation value at x. For brickwork Haar-random circuits of qudits measured at each site with probability p per layer, the circuit-averaged OTOC is a transfer-matrix contraction. It decays at late times as \lambda_*^{t} with \lambda_*=1-\tfrac{2(q-1)}{q}Np+O(p^{2}) for Np\ll1, and for sparse measurement in a large system the decay is Gaussian in time with variance 1/(\kappa p). Eight-qubit runs on Quantinuum&#x27;s H2 resolve the light cone and the decay inside it.</description></item><item><title>Optimal finite-copy readout of three-qubit entanglement with state retention</title><link>https://quantumresearch.center/news/papers/2611.08233/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.08233/</guid><pubDate>Sun, 08 Nov 2026 00:00:00 +0000</pubDate><category>Quantum information</category><description>Given n copies of an unknown three-qubit pure state, how likely can a fixed measurement be to certify, without false positives, that the state is in the GHZ class (nonzero three-tangle \tau)? How large can the coefficient be in an event whose probability is exactly proportional to \tau^{2}? And can such a certificate leave a copy of the unknown state intact? Fewer than four copies give no certificate. Four copies give optimal probability \tau^{2}/48. Five copies give 5\tau^{2}/72, a factor 10/3 more, and can return the unknown input on success; five is the minimum for that. At six copies certification and exact binary readout first differ: (39+2S)\tau^{2}/296 against \tau^{2}/8, where S is the sum of single-party purities. Local spin measurements with classical communication attain all of these optima.</description></item><item><title>Certifying quantum code and circuit distances at scale</title><link>https://quantumresearch.center/news/papers/2611.08247/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.08247/</guid><pubDate>Sun, 08 Nov 2026 00:00:00 +0000</pubDate><category>Quantum computing</category><description>The circuit distance, the fewest faults in a syndrome-extraction circuit that flip a logical observable without firing any detector, sets the leading order of the logical error rate. For qLDPC circuits with 10^{4} to 10^{5} fault mechanisms, papers usually report upper bounds from heuristic searches, and resource estimates for planned machines rest on assumed values. Can exact distances be certified at that scale? Writing both code and circuit distance as a tropical (min-plus) partition function and combining two dynamic programs, a bounded search and certified relaxations, the method certifies 70 of 74 benchmark instances in the authors&#x27; suite against 53 for all other exact solvers combined, and 95 against 80 on an independent benchmark. It certifies codes with up to 31,200 qubits and circuits with up to 8\times10^{5} fault mechanisms. An audit of 26 papers finds overestimated distances in 10, with a gap of at least eight. IBM&#x27;s two-gross [\![288,12,18]\!] memory circuit has circuit distance 16 with the standard schedule, not 18; other schedules reach 18 at one noisy cycle, at the cost of a ninth timestep per cycle.</description></item><item><title>Testing gravitationally induced entanglement with massive particles and quantum clocks</title><link>https://quantumresearch.center/news/papers/2611.08313/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.08313/</guid><pubDate>Sun, 08 Nov 2026 00:00:00 +0000</pubDate><category>Foundations of quantum mechanics</category><description>Proposed tests of whether gravity can entangle two masses can be explained by the Newtonian potential between fixed masses, which some argue admits a classical, non-local account. A test that needs a relativistic feature of gravity would close that loophole. The contribution of a clock&#x27;s internal energy to gravitating mass is such a feature, but the entanglement it generates between two clocks takes about 10^{41} s to appear. Replacing one clock by a delocalised levitated particle of about the Planck mass (M\sim10^{-8} kg), and the other by an array of N clocks, shortens the time scale by the particle&#x27;s mass and by \sqrt N. For N=10^{23} scandium-45 nuclear clocks in a centimetre-scale crystal, 450 µm from a particle delocalised by 0.1 µm, the authors estimate an entanglement (equivalently, dephasing) time of about 5\times10^{6} s, or 64 days (Eq. 9).</description></item><item><title>Upper and lower bounds for few-copy Gaussian tomography, and the absence of a fermionic warm regime</title><link>https://quantumresearch.center/news/papers/2611.07271/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.07271/</guid><pubDate>Sat, 07 Nov 2026 00:00:00 +0000</pubDate><category>Quantum information</category><description>Learning an m-mode Gaussian state to trace distance \epsilon takes \Theta(m^2/\epsilon^2) copies if all copies can be measured jointly. With one copy at a time, mixed states need more. Chen, Mele, Mele and Preskill showed that for bosons cold states need m^3/\epsilon^2 but warm states only m^2/\epsilon^2. They asked how this temperature crossover looks for finite-dimensional systems. Is there a warm regime for fermions, and what do measurements on blocks of k copies buy? Fermions have no warm regime: for every \beta_0&gt;0, quadratic Gibbs states with \beta\|h\|_F\le\beta_0 need \Theta(m^3/\epsilon^2) single-copy samples at accuracies resolving the ball. At the maximally mixed state, blocks of at most k copies need N&gt;\frac{m^3}{8{,}553{,}600\,k\,\epsilon^2}\qquad(\epsilon\le1/3600). An exact formula shows that the Fisher budget behind this bound is asymptotically attained. Near the vacuum, blocks need \Omega(m^3/(\epsilon^2\min\{\sqrt k,m\})). A particle-number measurement followed by the Nayak–Zhou qudit protocol attains this for every k on number-conserving fermionic and on all cold bosonic Gaussian states.</description></item><item><title>Extensions of the Haldane gap proof: higher dimensions, near degeneracy, fermions and tensor-network states</title><link>https://quantumresearch.center/news/papers/2611.07400/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.07400/</guid><pubDate>Sat, 07 Nov 2026 00:00:00 +0000</pubDate><category>Foundations of quantum mechanics</category><description>A recent paper by OpenAI proved that the spin-one Heisenberg chain is gapped in the thermodynamic limit, using only spectral information from a finite system. The argument, which this paper calls the purity bootstrap, compares the purity of the Gibbs state with that of a dual Gibbs state obtained by exchanging space and imaginary time. Does it work in more than one dimension, for phases with several nearly degenerate ground states, for fermions, and for wave functions rather than Hamiltonians? The bootstrap extends to every spatial dimension: a single finite ratio of partition functions above a fixed threshold certifies a size-independent gap. Summing over symmetry twists lets it handle near degeneracy. Finite calculations show that the 2+1-dimensional transverse-field Ising model for h/J\le1.8 has two low states split by at most Ce^{-cL^2}, and that the toric code in a field with h/J_m\le1/7 has four split by at most Ce^{-cL}, each with a gap above them. A fermionic version establishes a symmetric mass generation phase for t/J\le1/35. For the Jian–Zaletel spin-one PEPS the paper proves a correlation length below 8.012 lattice spacings.</description></item><item><title>Structured Quantum Hardness from Unstructured Assumptions</title><link>https://quantumresearch.center/news/papers/2611.07413/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.07413/</guid><pubDate>Sat, 07 Nov 2026 00:00:00 +0000</pubDate><category>Quantum computing</category><description>Languages in \mathsf{NP}\cap\mathsf{coNP} have short checkable certificates for both answers. The classic candidates for hard ones, factoring and discrete logarithm, fall to Shor&#x27;s algorithm, and lattice assumptions give certificates only on promise inputs. Bennett and Gill asked whether \mathsf{NP}\cap\mathsf{coNP} stays hard relative to a random oracle. Is there quantum-hard two-sided certification that arises from unstructured sources? If \mathsf{UP}\not\subseteq\mathsf{BQP}, then \mathsf{NP}^{\mathcal O}\cap\mathsf{coNP}^{\mathcal O}\not\subseteq\mathsf{BQP}^{\mathcal O} with probability one over a random oracle \mathcal O. Along the way the paper builds an unbounded-prover NIZK proof for \mathsf{NP} in the quantum random oracle model with no further assumptions. In the other direction, no fully black-box quantum reduction derives a worst-case quantum-hard \mathsf{NP}\cap\mathsf{coNP} problem from post-quantum injective one-way functions and indistinguishability obfuscation.</description></item><item><title>Information-Spectrum General Formulas for the Capacity Region of Classical-Quantum Multiple Access Channels</title><link>https://quantumresearch.center/news/papers/2611.07462/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.07462/</guid><pubDate>Sat, 07 Nov 2026 00:00:00 +0000</pubDate><category>Quantum information</category><description>Two senders transmit classical messages through a channel whose output is a quantum state. For memoryless channels the capacity region is known, but real channels may have memory or change with block length. The information-spectrum method gives capacity formulas for arbitrary channel sequences: Verdú–Han and Hayashi–Nagaoka for one sender, Han (1998) for the classical two-sender channel. For the classical-quantum multiple access channel only an outer bound (Kubo–Nagaoka 2015) was known. What is the exact region? For every sequence of cq-MACs, the capacity region (vanishing error) is the union over input-distribution sequences of the regions R_1\le\underline I_1, R_2\le\underline I_2, R_1+R_2\le\underline I_0, defined by three spectral inf-mutual information rates. This is the quantum counterpart of Han&#x27;s formula. For every 0\le\varepsilon&lt;1, the \varepsilon-capacity region equals the 2015 outer bound evaluated at the marginal states, so that bound is tight. Its consistency constraint turns out to be unnecessary.</description></item><item><title>Exponential mixing time for the Davies dynamics of the quantum random energy model</title><link>https://quantumresearch.center/news/papers/2611.08064/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.08064/</guid><pubDate>Sat, 07 Nov 2026 00:00:00 +0000</pubDate><category>Foundations of quantum mechanics</category><description>The quantum random energy model (QREM) puts an independent Gaussian energy of variance n on each of the 2^n computational-basis states and adds a transverse field. In its spin-glass phase, how long does it take to thermalise when weakly coupled to a bath through single-qubit Pauli operators? Lower bounds on mixing times for noncommuting random Hamiltonians were listed as open, because their eigenbasis, and hence the Davies jump operators, is not explicitly known. For every \beta&gt;\beta_c=\sqrt{2\log2} and every field 0\le\Gamma&lt;\Gamma_c(\beta), where e^{\beta\beta_c}=2\cosh(\beta\Gamma_c), the Davies mixing time satisfies \liminf_n\frac1n\log T_{\rm mix}\ge c_{\rm mix}&gt;0 almost surely. This holds for any detailed-balance rates whose maximum grows subexponentially, with or without dephasing terms, and without assuming primitivity.</description></item><item><title>Provable circuit-level thresholds for non-abelian topological phases</title><link>https://quantumresearch.center/news/papers/2611.08488/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.08488/</guid><pubDate>Sat, 07 Nov 2026 00:00:00 +0000</pubDate><category>Quantum computing</category><description>Abelian topological codes such as the toric code have shallow syndrome circuits and decoders with proven thresholds. Non-abelian phases could offer more powerful logical gates, but outside a few &quot;solvable&quot; cases (D_4, S_3) there was no explicit syndrome-extraction circuit and no circuit-level threshold proof. Earlier work on the double-Fibonacci phase gave only numerics under simplified noise. Can every non-chiral 2D topological phase serve as a fault-tolerant memory under realistic noise? For every non-chiral bosonic topological order given by a Turaev–Viro state sum, the paper constructs a local circuit that extracts syndromes and applies corrections. It pairs the circuit with a polynomial-time clustering decoder that runs on the fly. Under local stochastic circuit-level noise with rate below a constant threshold \epsilon_*, the logical error probability decays quasi-stretched-exponentially in the system size L. The paper also sketches how the scheme extends to logical gates built from defects.</description></item><item><title>Asymptotic advantage of quantum one-way and SMP communication for total functions</title><link>https://quantumresearch.center/news/papers/2611.07318/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.07318/</guid><pubDate>Fri, 06 Nov 2026 00:00:00 +0000</pubDate><category>Quantum information</category><description>For partial functions, with a promise on the inputs, quantum one-way communication can be exponentially cheaper than classical. For total functions, defined on every input, the question is how large a gap can be at all. Is there a total Boolean function with a polynomial gap between bounded-error quantum and randomised communication in the one-way and simultaneous-message (SMP) models, with public randomness allowed? Yes. Alice holds M\in\mathbb F_2^{d\times d} and Bob holds u,z\in\mathbb F_2^d, with input length n=d^2+2d. Let F_d(M;u,z)=1 exactly when (M+M^{\mathsf T})u=z and u^{\mathsf T}Mu=0. Then Q^{\parallel}(F_d) and Q^{\to}(F_d) are \Theta(\sqrt n), while R^{\to}(F_d) and R^{\parallel}(F_d) are \Theta(n). With 2d shared EPR pairs, a classical SMP protocol costs O(\sqrt n), and any entanglement still leaves \Omega(\sqrt n).</description></item><item><title>Frustration-freeness is decidable but unprovable</title><link>https://quantumresearch.center/news/papers/2611.07337/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.07337/</guid><pubDate>Fri, 06 Nov 2026 00:00:00 +0000</pubDate><category>Foundations of quantum mechanics</category><description>A translation-invariant nearest-neighbour Hamiltonian on an L\times L square lattice, with positive semidefinite bond terms of zero ground energy, is frustration-free if a single state is annihilated by every term. For one fixed L this is a finite linear-algebra question. Physics usually wants the answer for every L. Is that question decidable when the local dimension d is fixed? Fixing d does not settle it on its own: the spectral-gap problem is undecidable on the same inputs. For each d there is a single size L(d), the same for every Hamiltonian, such that frustration-freeness on the L(d)\times L(d) lattice implies it at every size (Theorem 1), so the problem is decidable for each fixed d. Yet, if ZFC is consistent, there is an explicit Hamiltonian with diagonal, commuting terms that is frustration-free at every size although ZFC cannot prove it (Theorem 3). The two fit together because no algorithm computes a valid cutoff for every d (Theorem 4); the cutoff grows at least like the busy-beaver function, L(am+b)\ge\mathrm{BB}(m).</description></item><item><title>Fidelity Determines the Minimum Error of Quantum Recovery</title><link>https://quantumresearch.center/news/papers/2611.07344/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.07344/</guid><pubDate>Fri, 06 Nov 2026 00:00:00 +0000</pubDate><category>Quantum information</category><description>A recovery after noise can be judged by its worst-input entanglement fidelity F, the probability of passing a test that the state and its entanglement with a reference survived. It can also be judged by its operational error D=\tfrac12\|\Phi-\mathrm{id}\|_\diamond, the largest change in any measurement probability. In general 1-F\le D\le\sqrt{1-F}. For a fixed noise channel and encoding, do the two coincide once each is optimised over recoveries? Holdsworth, Singh and Wilde proved equality when encoder and decoder share free randomness, and left the unassisted case open. They coincide. For every finite-dimensional channel \Phi there is an output unitary U with 1-F(\mathrm{Ad}_U\Phi)\le D(\mathrm{Ad}_U\Phi)\le1-F(\Phi)\le D(\Phi), so over any family of recoveries closed under final unitaries, including Kraus-rank caps, \inf D=1-\sup F. The unitary is the polar part of the Kraus combination weighted by the worst input&#x27;s amplitudes. The paper also gives a semidefinite program for the best final unitary when the error is below one half, formulas for recovery with a retained noise record, and robustness bounds. In a three-qubit calibration example the optimal correction has 20.3 percent lower operational error than the recovery that maximises average gate fidelity.</description></item><item><title>Quantum trajectory of a spin oscillator, continuous retrodiction beyond the Heisenberg uncertainty relation</title><link>https://quantumresearch.center/news/papers/2611.08104/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.08104/</guid><pubDate>Fri, 06 Nov 2026 00:00:00 +0000</pubDate><category>Foundations of quantum mechanics</category><description>The Heisenberg relation \Delta x\,\Delta p\ge1/2 limits how well a state predicts the outcomes of measuring two conjugate observables. It says nothing about guesses of a past measurement made with data from both before and after it. Can continuous monitoring of a macroscopic spin oscillator retrodict x, p and every rotated quadrature at once with variances below the standard quantum limit, and can this be kept up over long runs? In a paraffin-coated ^{87}Rb vapour cell with about 5.17\times10^{10} atoms, alternating stroboscopic QND measurements of \hat x_A and \hat p_A at rate \kappa^2\eta=2\pi\times1002 Hz were analysed forwards, with the state \rho(t), and backwards, with the effect matrix E(t). Prediction alone gave variances 0.88 dB above the standard quantum limit. Combining past and future data gave both variances 1.01\pm0.15 dB below it, so \Delta x\,\Delta p beat the Heisenberg value, and this held over 1.4 hours. Rotating the verification phase gave sub-SQL retrodicted variances for every quadrature, 0.388\pm0.025 on average against 0.5.</description></item><item><title>Quantum Advantage with Sign-Free Proofs: An Oracle Separation between StoqMA and MA</title><link>https://quantumresearch.center/news/papers/2611.08180/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.08180/</guid><pubDate>Fri, 06 Nov 2026 00:00:00 +0000</pubDate><category>Quantum computing</category><description>In \mathsf{StoqMA} the verifier receives a quantum witness, uses ancillas in |0\rangle and |+\rangle, applies only classical reversible gates (X, CNOT, Toffoli) and makes one Hadamard-basis measurement. The class sits between \mathsf{MA} and \mathsf{AM}, and if it admitted error reduction it would equal \mathsf{MA}. Its complete problems concern stoquastic, sign-problem-free Hamiltonians, where quantum Monte Carlo often works. Does this nearly classical verifier beat every classical \mathsf{MA} verifier, at least relative to an oracle? Yes. There is a classical XOR oracle \mathcal O with \mathsf{StoqMA}^{\mathcal O}\ne\mathsf{MA}^{\mathcal O} (Theorem 1.1). The separating problem asks whether a sparse, high-girth graph on 2^m vertices, given by a randomly relabelled adjacency-list oracle, has top eigenvalue at least n or at most 4\sqrt n. The verifier receives the Perron eigenvector and runs a Hadamard test that accepts with probability 1/2+\langle\psi|A|\psi\rangle/(2d). That is at least 3/4 for the YES graph and at most 1/2+1/\sqrt n for every NO graph. No \mathsf{MA} verifier with a polynomial witness and polynomially many queries can do this.</description></item><item><title>Polynomial-time classical simulation of boson and fermion sampling under thermal loss</title><link>https://quantumresearch.center/news/papers/2611.08444/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.08444/</guid><pubDate>Fri, 06 Nov 2026 00:00:00 +0000</pubDate><category>Quantum computing</category><description>Photonic sampling experiments lose a constant fraction of their particles. Does a fixed loss rate already make Haar-random boson or fermion sampling classically easy, without assuming that loss grows with system size, that outputs are dilute, or that circuits are shallow? Earlier simulation results each needed one of those extra conditions. For Fock-state boson sampling, Gaussian boson sampling with fixed uniform squeezing and fermion sampling with four-mode magic inputs, under thermal loss at any fixed transmissivity \eta&lt;1 (pure loss included), there is a classical sampler with error \varepsilon in total variation, with probability 1-\delta over Haar-random interferometers, in time polynomial in m, 1/\varepsilon and 1/\delta (Theorem III.1). If the ideal output is only polynomially flat, \chi^2(\rho_U\|\tau)\le m^{O(1)}, the time is (m/\varepsilon)^{O(\log(m/\varepsilon))} for any interferometer. It becomes polynomial when loss acts after each of \Omega(\log m) layers. Near full input filling, the noisy output is close to one fixed distribution, whatever the interferometer.</description></item><item><title>Algorithmic Wave-Particle Duality: Pathfinding in Welded Trees is Hard</title><link>https://quantumresearch.center/news/papers/2611.05912/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.05912/</guid><pubDate>Thu, 05 Nov 2026 00:00:00 +0000</pubDate><category>Quantum computing</category><description>In the welded trees problem, two binary trees of height n are joined at their leaves by a random cycle, vertices carry random labels, and an algorithm starts at one root. A quantum walk reaches the other root in polynomial time, whereas classical algorithms need exponentially many queries. The walk never records a route, and recording one destroys its interference. Can some other quantum algorithm efficiently output an entrance–exit path? The question had been open since the original paper on the problem. No. Under a distribution over welded trees graphs with a single-cycle weld, any q-query algorithm outputs an entrance–exit path with probability O\Bigl(\frac{q}{2^{n/3}}+\frac{n\,q^3}{2^n}\Bigr), so \tilde\Omega(2^{n/3}) queries are needed. This is tight up to factors polynomial in n: find the exit with the walk, then use collision finding to join a root-to-leaf path from each side in O(n\,2^{n/3}) queries.</description></item><item><title>Norm Bounds on Sums of Positive Operators with Applications to Monogamy Games and Quantum Key Distribution</title><link>https://quantumresearch.center/news/papers/2611.05943/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.05943/</guid><pubDate>Thu, 05 Nov 2026 00:00:00 +0000</pubDate><category>Quantum information</category><description>In the BB84 monogamy game, Alice measures n qubits in random bases, and two separated players, Bob and Charlie, must each guess her outcome string. Perfect guessing has optimal probability (\cos^2\tfrac\pi8)^n. If Bob may make \beta n errors and Charlie \gamma n, for which (\beta,\gamma) does the winning probability still decay exponentially? The existing bound certified decay only up to about 1.53% symmetric error, and the same weakness limited the one-sided device-independent QKD rate built on it. The winning probability decays exponentially if (1-2\beta)^2+(1-2\gamma)^2&gt;1, tends to one exponentially fast under the reverse strict inequality, and stays bounded away from zero on the circle itself. The symmetric threshold is \sin^2\tfrac\pi8\approx14.64\%. For one-sided device-independent BB84, where Bob may make an arbitrary joint measurement depending on the whole basis string, every key rate 0&lt;R&lt;1-2h_2(\gamma) is achievable, which is the standard BB84 rate with its 11% noise threshold.</description></item><item><title>Equivalence of Correlated Catalytic and Marginal Asymptotic Transformations in Quantum Resource Theories</title><link>https://quantumresearch.center/news/papers/2611.06573/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.06573/</guid><pubDate>Thu, 05 Nov 2026 00:00:00 +0000</pubDate><category>Quantum information</category><description>In correlated catalysis, an auxiliary system helps convert \rho into (approximately) \sigma, and is returned with exactly its original marginal, though it may end up correlated with the system. A catalyst built from many copies turns any marginal asymptotic conversion at rate one into a correlated-catalytic one. Does the converse hold? In particular, can a correlated catalyst make an undistillable entangled state distillable under LOCC? In every resource theory that allows classical control and processing, permutations, full-rank free states and free informationally complete measurements, \rho converts to \sigma by correlated catalysis if and only if the marginal asymptotic rate R_{\rm m}(\rho\to\sigma) is at least one. Under LOCC, correlated catalysts cannot increase distillable entanglement or distillable key, cannot activate bound entanglement, and cannot raise the two-way private capacity of a finite-dimensional channel.</description></item><item><title>A Quantum Lower Bound for Triangle Finding</title><link>https://quantumresearch.center/news/papers/2611.06751/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.06751/</guid><pubDate>Thu, 05 Nov 2026 00:00:00 +0000</pubDate><category>Quantum computing</category><description>Given the adjacency matrix of an N-vertex graph, how many quantum queries are needed to find a triangle? Upper bounds fell from Grover&#x27;s O(N^{3/2}) to O(N^{5/4}), but the only lower bound was the \Omega(N) inherited from unstructured search. Positive-weight adversary methods cannot beat O(N) here, because a triangle certificate has only three edges. Triangle finding needs \Omega(N^{13/12}) quantum queries, the first superlinear lower bound. The same bound holds for triangle detection and for detecting any fixed connected non-bipartite subgraph. For sparse graphs with \bar m edges in the range N\log N\lesssim\bar m\lesssim N^{3/2} the bound \Omega(N^{5/6}\bar m^{1/6}) is tight up to polylogarithmic factors.</description></item><item><title>Using topology to reveal all mutually unbiased bases in dimension six</title><link>https://quantumresearch.center/news/papers/2611.06917/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.06917/</guid><pubDate>Thu, 05 Nov 2026 00:00:00 +0000</pubDate><category>Foundations of quantum mechanics</category><description>Two orthonormal bases of \mathbb C^d are mutually unbiased when every overlap satisfies |\langle a_i|b_j\rangle|^2=1/d: certainty in one basis gives no information about the other. At most d+1 such bases exist, and the bound is reached in every prime-power dimension. Six is the first other dimension. Qubit and qutrit bases give three mutually unbiased bases there, and in 1991 Zauner conjectured that no fourth exists. Which sets exist at all had remained open. All sets of mutually unbiased bases in \mathbb C^6 are classified up to equivalence. Every pair comes from Tao&#x27;s matrix, from the Fourier matrix F_6, or from a completion H_+(\theta) built from four phases. Every triple belongs to one known two-parameter family or is the isolated Fourier triple. Neither kind of triple extends, so no four bases exist, N(6)=3. A second test on the same cover rules out quartets directly.</description></item><item><title>The most entangled states of four and seven qubits</title><link>https://quantumresearch.center/news/papers/2611.05757/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.05757/</guid><pubDate>Thu, 05 Nov 2026 00:00:00 +0000</pubDate><category>Foundations of quantum mechanics</category><description>No pure state of four or seven qubits is maximally entangled across every balanced cut, because absolutely maximally entangled states do not exist at those sizes. How entangled can such a state be on average over its balanced cuts? For four qubits, Higuchi and Sudbery conjectured in 2000 that their state M_4 maximises the mean entropy of the three 2|2 cuts. The Higuchi–Sudbery conjecture holds: every four-qubit pure state has mean 2|2 entropy at most 1+\tfrac12\log_23\approx1.792 bits, with equality only on the local-unitary orbits of M_4 and its complex conjugate. For seven qubits, the mean purity of the 35 cuts of type 3|4 is at least 121/917 and the mean entropy is at most 2.965356029\ldots bits. Each bound has a unique optimiser up to local unitaries and qubit permutations, and the two optimisers are different members of one icosahedral family.</description></item><item><title>On Random Purifications of Isometries and Channels</title><link>https://quantumresearch.center/news/papers/2611.04573/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.04573/</guid><pubDate>Wed, 04 Nov 2026 00:00:00 +0000</pubDate><category>Quantum information</category><description>The random purification channel turns copies of a mixed state into copies of a random purification, and has driven recent results in learning and cryptography. Tang, Wright and Zhandry asked whether the same trick lifts queries one level up the hierarchy of maps: can queries to an isometry simulate queries to a random unitary completion, and can queries to a channel simulate queries to a random isometry dilation? The first holds approximately and the second fails badly. An efficient, stateful simulator makes one forward query to an isometry V:N\to M per call and emulates T queries to a Haar-random completion with trace-distance error O(T\sqrt{N/(M-T)}). In contrast, two channel ensembles on dimension D can be told apart perfectly with two queries to any dilation, or with one quantum switch, while q channel queries give advantage only O(q^{3/2}/\sqrt D).</description></item><item><title>Autonomous cooling of Kerr-cat qubits to minutes-long bit-flip times</title><link>https://quantumresearch.center/news/papers/2611.04868/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.04868/</guid><pubDate>Wed, 04 Nov 2026 00:00:00 +0000</pubDate><category>Quantum computing</category><description>Cat qubits store a bit in two opposite coherent states of an oscillator. Bit flips are then suppressed exponentially in the photon number, which makes noise strongly biased and error correction cheaper. Kerr cats, which are confined by a driven double-well potential, allow fast gates, but excitations inside the wells cause hopping between them, and their bit-flip times had stayed at milliseconds. Can the excitations be removed without new drives or circuit elements? Yes. The three-wave interaction that produces the squeezing drive also couples excitations inside a well to the lossy readout resonator and Purcell filter. When the frequencies match, it drains the excitations. The bit-flip time grows by a factor of 1.82\pm0.06 per photon, from 52 µs at \bar n=7.4 to 448\pm57 s at \bar n=33.8. Fast Z gates leave the bit-flip time unchanged, and each readout flips the qubit with probability (5\pm1)\times10^{-7}.</description></item><item><title>Simple proof of conditions requiring maximal entanglement for local state verification and discrimination</title><link>https://quantumresearch.center/news/papers/2611.05317/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.05317/</guid><pubDate>Wed, 04 Nov 2026 00:00:00 +0000</pubDate><category>Quantum information</category><description>Two parties sharing an unknown state want to verify, with certainty and using only local operations and classical communication, whether it is a given entangled |\varphi\rangle. This needs an entangled resource |\tau\rangle. It was known that the resource needs Schmidt rank at least that of |\varphi\rangle, and that at equal rank it must be maximally entangled, but the second fact had only an algebraic-geometry proof. Is there a direct argument, and what does it imply for distinguishing bases? A self-contained linear-algebra proof of both statements, valid even for separable measurements. As a consequence, among resources of local dimension at most d, perfectly distinguishing a basis of \mathbb C^d\otimes\mathbb C^d that contains one full-Schmidt-rank state requires, and is achieved by, a maximally entangled state of \mathbb C^d\otimes\mathbb C^d. This holds for almost every basis, however weakly entangled its states are.</description></item><item><title>Breaking the quantum barriers for Graph Collision</title><link>https://quantumresearch.center/news/papers/2611.05356/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.05356/</guid><pubDate>Wed, 04 Nov 2026 00:00:00 +0000</pubDate><category>Quantum computing</category><description>In graph collision, a graph on n vertices is known in advance, some vertices are marked, and the task is to decide with as few queries as possible whether some edge has both endpoints marked. It is a subroutine for triangle finding. The best quantum algorithm for arbitrary graphs had used O(n^{2/3}) queries since 2005, the lower bound was \Omega(\sqrt n), and some had conjectured that n^{2/3} was optimal. The conjecture is false. A first algorithm uses \tilde O(n^{92/139})\approx n^{0.662} queries and a refined one uses \tilde O(n^{11/17})\approx n^{0.647}. The same bound applies to any Boolean function whose positive inputs have certificates of size two, provided the alphabet is small. In the other direction, an adversary matrix gives \Omega(\sqrt{n\log n}) for a points-and-lines graph, beating the \sqrt n barrier for positive-weight adversaries.</description></item><item><title>Analog quantum simulation of paraparticle statistics</title><link>https://quantumresearch.center/news/papers/2611.03908/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.03908/</guid><pubDate>Wed, 04 Nov 2026 00:00:00 +0000</pubDate><category>Foundations of quantum mechanics</category><description>Every particle we know is a boson or a fermion, and older proposals for other statistics in three dimensions turned out to be bosons or fermions with a hidden local label. Wang and Hazzard recently proposed R-paraparticles, whose internal &quot;colour&quot; is a nonlocal property of the many-body state and changes under exchange by a matrix rather than a sign. Can such statistics be produced and seen in a laboratory system? On a 16-transmon lattice, the authors emulate a two-colour (m=2) paraparticle chain of up to four sites. Exchanging two paraparticles gives a phase of (1.00\pm0.01)\pi. Two paraparticles meeting at a 50:50 beamsplitter antibunch whatever their colours. And a single site thermalised against a 14-qubit bath reaches the occupation 2x/(1+2x), which is neither Bose–Einstein nor Fermi–Dirac.</description></item><item><title>Tight Quasiprobabilistic Entropic Uncertainty Relations for Discrete Quantum Systems</title><link>https://quantumresearch.center/news/papers/2611.04009/</link><guid isPermaLink="true">https://quantumresearch.center/news/papers/2611.04009/</guid><pubDate>Wed, 04 Nov 2026 00:00:00 +0000</pubDate><category>Foundations of quantum mechanics</category><description>The Wehrl–Lieb theorem says coherent states minimise the entropy of the Husimi function. The analogous claim for the Wigner function, that pure Gaussian states minimise the Wigner entropy among states with a positive Wigner function, has been disproved. Does the claim hold for the discrete quasiprobabilities used in quantum information, where some positive states are mixed and extremal? Yes, for Kirkwood–Dirac distributions built on mutually unbiased bases and for Gross–Wigner distributions of odd-dimensional qudits. For every state whose distribution has a nonnegative real part, H(A)+H(B)\ge H^{\mathrm{MH}}\ge-\ln\mathrm{Tr}\rho^2+\ln d\ge\ln d, and the last bound is reached only on pure positive states. For Kirkwood–Dirac distributions, states with large nonpositivity (mana) must also have large Rényi-½ uncertainty.</description></item></channel></rss>
