Education / Quantum Information Theory

Quantum Information Theory · Chapter 02

Quantum Channels and Dilations

How can we certify a physical process, including its action on entangled inputs?

In this chapter · 3 sections
  1. 2.1 Complete positivity
  2. 2.2 Kraus operators and environments
  3. 2.3 Comparing devices
Reading guide · preparation and approach

Starting point: Chapter 1; tensor products, partial traces, and matrix multiplication.

Anchor example: Amplitude damping of one half of a Bell pair.

Method: Compare Kraus, Choi, and isometric descriptions of the same map.

Watch for: Positivity on isolated inputs does not imply complete positivity.

This lesson includes explanations, worked examples, and problems with solutions. Advanced results whose proofs are outside the chapter are identified explicitly.

2.1 Complete positivity

2.1.1 An entangled input is a stronger test

A channel \(\mathcal N:A\to B\) is linear, completely positive, and trace preserving. Linearity respects preparation mixtures. Trace preservation keeps total probability one. Complete positivity requires \(\operatorname{id}_R\otimes\mathcal N\) to preserve positivity for every reference system, because a device must work when its input is part of a larger experiment. The reference need not be available to the device.

Ordinary transposition is a useful counterexample. It preserves the eigenvalues and trace of an isolated density matrix. Apply it to the second half of \(|\Phi\rangle=(|00\rangle+|11\rangle)/\sqrt2\), however. The resulting operator is one half of the swap operator. Its antisymmetric eigenvector \((|01\rangle-|10\rangle)/\sqrt2\) has eigenvalue \(-1/2\). This is not a state. Positivity alone therefore fails the physical consistency test.

We fix the Choi convention explicitly. Let \(|\Omega\rangle=\sum_i|i\rangle_R|i\rangle_A\), without normalization, and define \(J_{\mathcal N}=(\operatorname{id}_R\otimes\mathcal N)(|\Omega\rangle\langle\Omega|)\). Complete positivity is equivalent to \(J_{\mathcal N}\ge0\); trace preservation is equivalent to \(\tr_BJ_{\mathcal N}=I_R\). Thus \(\tr J_{\mathcal N}=d_A\), not one. The normalized Choi state is \(J/d_A\). The reconstruction formula is \(\mathcal N(X)=\tr_R[(X^T\otimes I)J]\), in the basis used for \(|\Omega\rangle\).

Worked check 2.1. What is the trace of the Choi matrix of the identity qubit channel?

Reasoned solution

It is 2: \(J=|\Omega\rangle\langle\Omega|\) and \(\langle\Omega|\Omega\rangle=2\). Dividing by 2 gives a Bell-state density matrix.

2.2 Kraus operators and environments

2.2.1 Where the missing coherence goes

A Kraus representation writes \(\mathcal N(X)=\sum_kK_kXK_k^\dagger\), with \(\sum_kK_k^\dagger K_k=I\). It is completely positive because each term stays positive even after adjoining a reference. Trace preservation follows by moving factors around the trace. Conversely, a positive Choi matrix can be spectrally decomposed and its eigenvectors reshaped into Kraus matrices; this proves the finite-dimensional representation theorem.

For amplitude damping, use \(K_0=\operatorname{diag}(1,\sqrt{1-\gamma})\) and \(K_1=\sqrt\gamma|0\rangle\langle1|\), where \(0\le\gamma\le1\). An input with entries \(\rho_{00}=a,\rho_{01}=b,\rho_{11}=1-a\) becomes

\[\mathcal N(\rho)=\begin{pmatrix}a+\gamma(1-a)&\sqrt{1-\gamma}\,b\\\sqrt{1-\gamma}\,b^*&(1-\gamma)(1-a)\end{pmatrix}.\]

Define an isometry \(V|\psi\rangle=\sum_kK_k|\psi\rangle|k\rangle_E\). Completeness gives \(V^\dagger V=I\); discarding \(E\) yields the channel. Discarding \(B\) instead defines a complementary channel, which records what the environment learns. Kraus representations are not unique, so their labels are not automatically physical detector outcomes. An actual measurement of the environment supplies an instrument and a classical record.

The equivalence of these representations is treated in Watrous, Chapter 2. We use the isometry later to compare information reaching the receiver and environment.

Worked check 2.2. Apply damping with γ=0.36 to |+⟩.

Reasoned solution

The output is \(\begin{pmatrix}0.68&0.4\\0.4&0.32\end{pmatrix}\). Its trace is one and determinant is 0.0576, so it is positive. Damping changes populations as well as coherence.

2.3 Comparing devices

2.3.1 A reference can expose hidden errors

Comparing channels on a few chosen states does not certify their behavior on every input. A stronger distance allows a reference: \(\|\mathcal N-\mathcal M\|_\diamond=\max_{\rho_{RA}}\|(\operatorname{id}_R\otimes(\mathcal N-\mathcal M))(\rho_{RA})\|_1\), where for channel differences a reference of input dimension suffices. Equal-prior single-use discrimination succeeds with probability \(1/2+\|\mathcal N-\mathcal M\|_\diamond/4\). This characterization is a theorem, not a conclusion from a small test set.

Consider identity versus complete dephasing on a qubit. Both act identically on \(|0\rangle\) and \(|1\rangle\); basis-state testing misses the error entirely. On \(|+\rangle\), the outputs are \(|+\rangle\langle+|\) and \(I/2\), whose trace distance is one half. This already permits success 0.75. It proves a lower bound on the optimized device-discrimination success. To establish optimality one still needs an upper bound.

For a sequence of devices, the triangle inequality and contraction by channels imply a useful telescoping bound: replacing \(m\) devices whose diamond distances are at most \(\delta_i\) changes the overall channel by at most \(\sum_i\delta_i\). This is conservative but applies to entangled and adaptive inputs when the surrounding operations are channels. State-specific accuracy cannot simply be substituted into this worst-case statement.

Worked check 2.3. What is the diamond distance between identity and the Pauli-X channel?

Reasoned solution

Input |0⟩ produces the orthogonal outputs |0⟩ and |1⟩, with trace norm difference 2. No pair of channels has diamond distance greater than 2, so the distance is exactly 2 and one use distinguishes them perfectly.

Summary

Questions and worked problems

These exercises draw on the whole chapter. Attempt each question before opening a hint, explain your reasoning, then compare it with the worked solution.

1. Quick check §

State the trace-preserving condition on Kraus operators.

Hint 1

Move the Kraus factors around a trace.

Worked solution

\(\sum_kK_k^\dagger K_k=I\). The opposite ordering describes unitality, which is different.

Revisit the relevant explanation

2. Quick check §

What is the Choi trace for a qutrit-input channel in our convention?

Hint 1

Take the trace of the partial-trace condition.

Worked solution

It is 3, regardless of the output dimension.

Revisit the relevant explanation

3. Quick check §

Why is a negative Choi eigenvalue a failure certificate?

Hint 1

Use the entangled test input.

Worked solution

The normalized Choi matrix is the output on half of a maximally entangled state. A negative eigenvalue makes that output nonphysical.

Revisit the relevant explanation

4. Worked problem §

Compute amplitude damping on |1⟩ at γ=0.2.

Hint 1

Evaluate each Kraus branch.

Worked solution

The output is diag(0.2,0.8). The environment records a jump with probability 0.2.

Revisit the relevant explanation

5. Worked problem §

Is amplitude damping unital at nonzero γ?

Hint 1

Apply it to I/2.

Worked solution

No. The output is diag((1+γ)/2,(1−γ)/2), unequal to I/2 for γ>0.

Revisit the relevant explanation

6. Worked problem §

Find an isometry for the dephasing map \((1-p)\rho+pZ\rho Z\).

Hint 1

Attach an orthogonal label to each Kraus term.

Worked solution

\(V|\psi\rangle=\sqrt{1-p}|\psi\rangle|0\rangle+\sqrt p Z|\psi\rangle|1\rangle\). Orthogonal labels give \(V^\dagger V=I\), and tracing them out gives the desired map.

Revisit the relevant explanation

7. Worked problem §

Bound a four-gate circuit’s diamond error if each replacement has distance at most 0.003.

Hint 1

Use telescoping and the triangle inequality.

Worked solution

The distance is at most 0.012, hence the output trace distance is at most 0.006 for any input and reference.

Revisit the relevant explanation

8. Misconception §

Does a positive map always have a positive Choi matrix?

Hint 1

Recall partial transposition of a Bell state.

Worked solution

No. Complete positivity, not mere positivity, is equivalent to Choi positivity.

Revisit the relevant explanation

9. Misconception §

Does measuring computational-basis inputs certify an identity channel?

Hint 1

Compare complete dephasing.

Worked solution

No. Dephasing agrees on every computational-basis state while erasing off-diagonal coherence.

Revisit the relevant explanation

10. Extension §

Show that mixing two channels is again a channel.

Hint 1

Combine their Kraus lists with square-root weights.

Worked solution

For weight t, use √t times the first list and √(1−t) times the second. Completeness follows from tI+(1−t)I=I; the resulting map is the desired mixture.

Revisit the relevant explanation

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